University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 6 - Work and Kinetic Energy - Problems - Exercises - Page 197: 6.44

Answer

(a) v = 2.0 m/s (b) v = 2.0 m/s (c) v = 1.73 m/s

Work Step by Step

To find the work done by the force, we can calculate the area under the Force versus x graph. (a) From x = 0 to x = 3.0 m: W = 2.0 J + 2.0 J = 4.0 J We can use the work to find the speed $v$. $K_2 - K_1 = W$ $\frac{1}{2}mv^2 - 0 = 4.0~J$ $v^2 = \frac{8.0~J}{m}$ $v = \sqrt{\frac{8.0~J}{2.0~kg}}$ $v = 2.0~m/s$ (b) From x = 0 to x = 4.0 m: W = 2.0 J + 2.0 J + 0 = 4.0 J We can use the work to find the speed $v$. $K_2 - K_1 = W$ $\frac{1}{2}mv^2 - 0 = 4.0~J$ $v^2 = \frac{8.0~J}{m}$ $v = \sqrt{\frac{8.0~J}{2.0~kg}}$ $v = 2.0~m/s$ (c) From x = 0 to x = 7.0 m: W = 2.0 J + 2.0 J + 0 - 1.0 J= 3.0 J We can use the work to find the speed $v$. $K_2 - K_1 = W$ $\frac{1}{2}mv^2 - 0 = 3.0~J$ $v^2 = \frac{6.0~J}{m}$ $v = \sqrt{\frac{6.0~J}{2.0~kg}}$ $v = 1.73~m/s$
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