University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 6 - Work and Kinetic Energy - Problems - Exercises - Page 194: 6.1

Answer

See work.

Work Step by Step

a. Use equation 6.2. The angle between the force and the displacement is $0^{\circ}$. $$(2.40N)(1.50m)cos0^{\circ}=3.60 J$$ b. Use equation 6.2. The angle between the force and the displacement is $180^{\circ}$. $$(0.600N)(1.50m)cos0^{\circ}=-0.900 J$$ c and d. Use equation 6.2. The angle between the force and the displacement is $90^{\circ}$. The cosine is zero so there is no work done. Whenever a force acts perpendicular to the direction of motion, its contribution to the net work is zero. e. Add up the work done by all 4 forces to find 2.70 J.
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