University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 5 - Applying Newton's Laws - Problems - Exercises - Page 162: 5.32

Answer

$t = 4.71~s$

Work Step by Step

We can find the maximum possible acceleration such that the force of static friction can provide the required force to accelerate the toolbox. $F_f = ma$ $mg~\mu_s = ma$ $a = g~\mu_s = (9.80~m/s^2)(0.650)$ $a = 6.37~m/s^2$ We can find the time to accelerate to $v = 30.0~m/s$. $t = \frac{v-v_0}{a} = \frac{30.0~m/s-0}{6.37~m/s^2}$ $t = 4.71~s$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.