University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 34 - Geometric Optics - Problems - Discussion Questions - Page 1151: Q34.6

Answer

See explanation.

Work Step by Step

The mirror equation is $\frac{1}{s}+\frac{1}{s’}=\frac{1}{f}$. If f is positive (concave spherical mirror), and s is positive, then s’ is positive (real image) as long as the object distance s is greater than f. For a convex spherical mirror, where f is negative, and s is positive, the image distance s’ is always negative (virtual image) for any value of s. A single convex spherical mirror always produces virtual images.
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