University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 33 - The Nature and Propagation of Light - Problems - Exercises - Page 1105: 33.9

Answer

$2.51\times10^8m/s$.

Work Step by Step

Use Snell’s law to find the index of refraction of the plastic. The angles are measured from the normal to the interface. $$n_a sin\theta_a= n_b sin\theta_b$$ $$n_b=n_a(\frac{sin \theta_a}{sin \theta_b}) $$ $$n_b=1.00(\frac{ sin62.7^{\circ}}{ sin48.1^{\circ}}) =1.194$$ Now find the speed. $$n_b=\frac{c}{v}=1.194$$ $$v=\frac{c}{n}=\frac{3.00\times10^8m/s }{1.194 }=2.51\times10^8m/s $$
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