University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 33 - The Nature and Propagation of Light - Problems - Exercises - Page 1105: 33.6

Answer

467 nm.

Work Step by Step

The wavelength in water is shorter by a factor of n than it is in air. Find the wavelength in air. $$\lambda_w=\frac{\lambda_0 }{n_{water}}=526nm $$ $$\lambda_0=(1.333)(526nm)=701nm$$ The wavelength in benzene is shorter by a factor of n than it is in air. Find the wavelength in air. $$\lambda_b=\frac{\lambda_0 }{n_{benzene}}=\frac{701nm }{1.501} =467nm$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.