Answer
$71.8^{\circ} $.
Work Step by Step
Apply Snell’s law to the refraction at the interface.
$$n_a sin\theta_a= n_b sin\theta_b$$
$$1.70 sin62.0^{\circ}=1.58 sin\theta_b$$
$$ \theta_b=71.8^{\circ} $$
The ray refracts into a material of smaller n. It speeds up and bends away from the normal.