University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 32 - Electromagnetic Waves - Problems - Exercises - Page 1076: 32.49

Answer

See explanation.

Work Step by Step

a. The intensity of the light beam is $ I= (\frac{1}{2}\epsilon_0 c)E^2_{max}$. Therefore, a graph of $I$ versus $E^2_{max}$ should be a straight line with a slope of $\frac{1}{2}\epsilon_0 c$. b. $\frac{1}{2}\epsilon_0 c=1.33\times10^{-3}$ $$c=\frac{(2)( 1.33\times10^{-3})}{(8.854\times10^{-12}F/m)}=3.00\times10^8m/s$$ This is the expected answer.
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