Answer
See explanation.
Work Step by Step
a. $X_L=2 \pi fL=2 \pi (80Hz)(3.00H)=1510\Omega $.
b. Solve $X_L=2 \pi fL$ for the inductance.
$$L=\frac{X_L}{2 \pi f}=\frac{120\Omega }{2 \pi (80Hz)}=0.239H$$
c. $X_C=\frac{1}{2 \pi fC}=\frac{1}{2 \pi (80Hz)(4.00\times10^{-6}F)}=4.97\times10^{2}\Omega$.
d. Solve $X_C=\frac{1}{2 \pi fC}$ for the capacitance.
$C=\frac{1}{2 \pi fX_C}=\frac{1}{2 \pi (80Hz)( 120\Omega)}=1.66\times10^{-5}F$
