Answer
$C=1.33\times10^{-5}F$.
Work Step by Step
$X_C=\frac{V}{I}=\frac{170V}{0.850A}=200\Omega$
Solve $X_C=\frac{1}{2 \pi fC}$ for the capacitance.
$C=\frac{1}{2 \pi fX_C}=\frac{1}{2 \pi (60.0Hz)( 200\Omega)}=1.33\times10^{-5}F$
University Physics with Modern Physics (14th Edition)
by Young, Hugh D.; Freedman, Roger A.
Published by
Pearson
ISBN 10:
0321973615
ISBN 13:
978-0-32197-361-0
Chapter 31 - Alternating Current - Problems - Exercises - Page 1044: 31.7
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