University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 30 - Inductance - Problems - Exercises - Page 1013: 30.2

Answer

a. $M=6.82\times10^{-3}H$. b. $\Phi_{B2}=3.27\times10^{-4}Wb $. c. $|\epsilon_1|=2.46mV$.

Work Step by Step

a. $|\epsilon_2|=M|\frac{di_1}{dt}|$ $$M=|\frac{\epsilon_2}{di_1/dt}|$$ $$M=\frac{1.65\times10^{-3}V}{0.242A/s}=6.82\times10^{-3}H$$ b. $\Phi_{B2}=\frac{Mi_1}{N_2}=\frac{(6.82\times10^{-3}H)(1.20A)}{25}=3.27\times10^{-4}Wb $. c. $|\epsilon_1|=M|\frac{di_2}{dt}|=(6.82\times10^{-3}H)(0.360A/s)=2.46mV$.
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