University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 3 - Motion in Two or Three Dimensions - Problems - Exercises - Page 99: 3.83

Answer

(b) 0.47 s

Work Step by Step

The seed is launched at 90 degrees, so it will go straight up. Assume up to be positive. The highest possible speed is $u = 4.6 m/s$. At the highest point, the velocity $v = 0$. Using $ v = u + at$ (and using $a = -g$), we get $0 = 4.6 - 9.8t \implies t = 0.47 s$.
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