University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 3 - Motion in Two or Three Dimensions - Problems - Exercises - Page 93: 3.5

Answer

b) a_{av,x}=-8.67m/s a_{av,y}=-2.33m/s c)a= 8.98m/s^{s} angle = 195^{\circ}

Work Step by Step

b) a_{av,x}=change in v in x-direction/change in time= (-170-90)/30=-8.67m/s a_{av,y}= 40-110/30=-2.33m/s c)a=\sqrt ((-8.667^{2})+ (-2.333^{2})) = 8.98m/s^{s} tan \theta= a_{av,y}/a_{av,x = 0.269 \theta = 15^{\circ} Therefore, the angle is 180+15 = 195^{\circ}, since the components are in the third quadrant
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