University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 3 - Motion in Two or Three Dimensions - Problems - Exercises - Page 93: 3.10

Answer

1.29 m/s.

Work Step by Step

The diver should travel 1.75 m horizontally in the time that she falls 9.00 m vertically. Find the time to fall 9.00 m. $y-y_o=v_{oy}t+0.5at^2$ $-9.00m= 0 + (-4.90m/s^2)t^2$ $t=\sqrt{\frac{-9.00m}{-4.90m/s^2}}=1.355 s$ Now find the velocity needed to travel 1.75 m horizontally in that time. $v_x = \frac{1.75m}{1.355s}=1.29 m/s$
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