Answer
See explanation.
Work Step by Step
a. Each slab of flowing blood is like an object with maximum width d. It moves perpendicular to the field at speed v. $\epsilon=vBL$ becomes $\epsilon=vBd$.
b. $B=\frac{\epsilon}{vd}=\frac{0.0010V}{(0.15m/s)(0.0050m)}=1.3T$
c. The blood vessel has a cross-sectional area of $\pi (d/2)^2$. The volume of blood that flows past a point in time t is $\frac{\pi d^2 vt}{4}$.
The volume flow rate is volume/time.
$$R=\frac{\pi d^2 vt}{4}\frac{1}{t}=\frac{\pi d^2 v}{4}$$
From before, $v=\frac{\epsilon}{Bd}$
$$R=\frac{\pi d^2}{4}\frac{\epsilon}{Bd}=\frac{\pi \epsilon d}{4B}$$
