Answer
6.48 mN to the left.
Work Step by Step
The magnetic flux through the loop is decreasing.
The motional emf is vBL. Divide emf by the resistance to find the current.
$$I=\frac{vBL}{R}$$
The force is given by $ILB$.
$$F=\frac{vBL}{R}LB=\frac{(3.00m/s)(0.0150m)^2(2.40T)^2}{0.600\Omega}=6.48mN$$
By Lenz’s law, the force on the left-hand end of the loop is to the left, which would pull the loop back into the field and stop the flux from decreasing.
