Answer
90.3V.
Work Step by Step
Rotating the coil changes the magnetic flux through it. This induces an emf. Apply Faraday’s law.
$$|\epsilon_{av}|=N|\frac{\Delta \Phi_B}{\Delta t}|$$
$$\Phi_B =BAcos \phi$$
$$\phi_i=53.0^{\circ}$$
$$\phi_f=0^{\circ}$$
Calculate the emf.
$$|\epsilon_{av}|=NBA|\frac{cos \phi_f –cos \phi_i }{\Delta t}|$$
$$|\epsilon_{av}|=(80)(1.70T)(0.250m)(0.400m)|\frac{\cos0^{\circ}-cos 53.0^{\circ}}{0.0600s}|=90.3V$$
