Answer
a. 34 V.
b. Counterclockwise.
Work Step by Step
Apply Faraday’s law.
Let +z be the positive direction for the area vector $\vec{A}$. The initial flux is positive, and the final flux is zero.
a. $$\epsilon=-\frac{\Delta \Phi_B}{\Delta t}$$
$$\epsilon=-\frac{0-(1.5T)\pi(0.120m)^2}{0.0020s}=+34V$$
b. The emf is positive and the loop’s area vector is toward the viewer. By the right hand rule, the induced current is counterclockwise.
