University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 29 - Electromagnetic Induction - Problems - Exercises - Page 981: 29.2

Answer

a. $1.44\times10^{-5}Wb$, 0. b. 0.36mV.

Work Step by Step

a. $\Phi_{B,i}=BAcos0^{\circ}=(6.0\times10^{-5}T)(12\times10^{-4}m^2)(1)=7.2\times10^{-8}Wb$ The total flux is $N \Phi_{B,i}=(200)( 7.2\times10^{-8}Wb)=1.44\times10^{-5}Wb $ Afterward the flux is zero. $\Phi_{B,f}=BAcos90^{\circ}=0Wb $ b. $|\epsilon|= |\frac{\Delta \Phi_{B} }{\Delta t}|$ $$|\epsilon|= |\frac{\Phi_{B,f}-\Phi_{B,i}}{\Delta t}|$$ $$|\epsilon|= |\frac{0-1.44\times10^{-5}Wb }{0.040s}|=0.36mV$$
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