Answer
a. 17.1 mV.
b. 28.5 mA.
Work Step by Step
a. $|\epsilon|=A\frac{dB}{dt}=(0.09000m^2)(0.190T/s)=0.0171V$.
b. $I=\frac{\epsilon}{R}=\frac{0.0171V}{0.600\Omega}=0.0285A$
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