University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 23 - Electric Potential - Problems - Exercises - Page 779: 23.39

Answer

$V = 760 \mathrm{V}$

Work Step by Step

The electric field $E$ is related to the separated distance and the potential difference $V$ between the two plates. The separated distance here represents the radius of the sphere $R$ and the potential will be in the form \begin{aligned} V &=E R \\ &=(0.2\mathrm{m})(3800 \mathrm{V} / \mathrm{m}) \\ &=\boxed{760 \mathrm{V}} \end{aligned}
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