Answer
Under these hypothetical conditions, Gauss’s Law will not be valid.
Work Step by Step
Under these hypothetical conditions, consider a spherical Gaussian surface with a point charge at its center. The electric field has the same strength everywhere on the surface, and the electric field flux equals the electric field strength multiplied by the surface area.
Now, double the radius of the Gaussian surface. The electric field strength falls by a factor of 8 under these hypothetical conditions, while the surface area increases by a factor of 4.
The new electric flux is now only half of what it was before.
Gauss’s Law states that the flux depends on the enclosed charge, but this is a counterexample. The 2 closed surfaces have the same enclosed charge, but different electric flux through themselves.
