Answer
(a) $a = 1.7~m/s^2$
(b) It would take 12 seconds to travel the length of the ramp.
(c) The traffic would move 240 meters.
Work Step by Step
(a) We can calculate the acceleration.
$a = \frac{v^2-v_0^2}{2x} = \frac{(20~m/s)^2-0}{(2)(120~m)} = 1.7~m/s^2$
(b) $t = \frac{v-v_0}{a} = \frac{20~m/s-0}{1.7~m/s^2} = 12~s$
It would take 12 seconds to travel the length of the ramp.
(c) $x = vt = (20~m/s)(12~s) = 240~m$
The traffic would move 240 meters.
