Answer
(a) T increases
(b) $W = 4800 J $
Work Step by Step
(a) The relationship between P and T is $pV = nRT$. The temperature increases since $pV$ increases.
(b) The work done is the area under the blue line, so
$W = \frac{1}{2} (p_b + p_a )(V_b - V_a)$
$W = \frac{1}{2} (2.40×10^5 Pa)(0.0400 m^3)$
$W = 4800 J $
