Answer
a) We draw the diagram.
$A \longrightarrow B$: Constant volume
$B \longrightarrow C$: Constant pressure.
b) $-40000 \hspace{0.5mm}J$
Work Step by Step
We know the work done is the area under the $p-V$ curve.
From the diagram, the $A \longrightarrow B$ process has no area under the curve. So work done is zero.
For the process $B \longrightarrow C$, we have work done on the system. So the work done by the system is negative.
Work done now $=5\times 10^5\times (0.12-0.20)\hspace{1mm}J=-40000\hspace{0.5mm}J$.
