Answer
$(a) W = 1.67 \times 10^5 J $
$(b) \Delta U = 2.033 \times 10^6 J$
Work Step by Step
$(a) $ The work done is
$ W = p(V_f - V_i)$
and $p = 2 \space atm = 2.03 \times 10^5 Pa$
$ W = (2.03 \times 10^5 Pa)(0.824 m^3 - 1.00 \times 10^{-3} m^3) $
$ W = 1.67 \times 10^5 J$
$(b)$ The increase in internal energy when added energy is $2.20 \times 10^6 J/kg$
$\Delta U = \Delta Q - W$
$\Delta U =2.20 \times 10^6 J -1.67 \times 10^5 J$
$\Delta U = 2.033 \times 10^6 J $
