Answer
a) $P-V$ diagram is shown in the figure
b) $W = 1330.24 J$
Work Step by Step
a) Since the process is carried out under constant pressure, the $P-V$ diagram is a straight line parallel to the $V$ axis.
b) The work done in this process is $P\Delta V$. From the ideal gas equation, we see that
$PV = nRT$
$\implies P\Delta V = nR\Delta T$,
when $P$ and $n$ are kept constant. Thus the work done by $n=2$ moles of gas on going isobarically from $T_1 = 27^{\circ}\mathrm{C}$ to $T_2 = 107^{\circ}\mathrm{C}$ is
$W = nR\Delta T = 2\times 8.314\times (107-27) \mathrm{J} = 1330.24 \mathrm{J}$
