Answer
The internal energy change is greater than the heat added.
Work Step by Step
Heat entered the ice and work was done on the ice. Both effects increase the ice’s internal energy, so the resulting internal energy change is greater than the heat alone.
Mathematically, the volume V decreased, so work was done on the water by its surroundings, i.e., W $\lt$ 0.
$\Delta U=Q-W$, and with negative $W$, $\Delta Q$ exceeds Q.
