Answer
(a) $8.04 \times 10^4 J$
(b) $6.7 \min$
Work Step by Step
For (a):
The heat required is $Q = mc\Delta T$. For water, $c = 4.19 \times 10^3 J/kgK$. So $Q = (0.320)(4.19 \times 10^3)(60) = 8.04 \times 10^4 J$.
For (b):
We note that $power = \frac{energy}{time}$. So the time $t = \frac{energy}{power} = \frac{Q}{P} = \frac{8.04 \times 10^4}{200} = 402 \ s = 6.7 \min$
