Answer
$0.01995 \hspace{1mm}m^3$
Work Step by Step
The coefficient of volume expansion of ethanol is $75\times10^{-5} \hspace{2mm} {}^oC^{-1}=\beta$.
Change in volume is $\Delta V$.
Change in temperature $=(18-32) \hspace{1mm}{}^0C=-14\hspace{1mm}{}^0C=\Delta T$
Initial volume $=1.90 \hspace{1mm}m^3=V_0$
We know, $\Delta V=V_0\beta \Delta T$.
Putting the values we get, $\Delta V=-0.01995 \hspace{1mm}m^3$.
The volume of ethanol decreases by $0.01995 \hspace{1mm}m^3$. This much amount of ethanol can be additionally put.
