University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 17 - Temperature and Heat - Problems - Exercises - Page 575: 17.15

Answer

$49.4^{\circ}C$

Work Step by Step

We know that $\Delta V = V_0\beta \Delta T$. For copper, $\beta = 5.1 \times 10^{-5} \ {^{\circ}}C^{-1}$, and $\frac{\Delta V}{V_{0}} = 0.15 \times 10^{-2}.$ Then $\Delta T = \frac{\Delta V/V_0}{\beta} = \frac{0.15 \times 10^{-2}}{5.1 \times 10^{-5}} = 29.4 ^{\circ} C.$ So the final temperature is $(20+29.4) ^{\circ} C = 49.4 ^{\circ}C.$
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