Answer
$a.\quad-81.0^{\mathrm{o}}\mathrm{F}$
$b.\quad 134.1^{\mathrm{o}}\mathrm{F}$
$c.\quad 88.0^{\mathrm{o}}\mathrm{F}$
Work Step by Step
Conversion equation 17-1: $\quad T_{\mathrm{F}}=\displaystyle \frac{9}{5}T_{\mathrm{C}}+32^{\mathrm{o}}$.
$a.\displaystyle \quad T_{\mathrm{F}}=\frac{9}{5}(-62.8)+32=-81.0^{\mathrm{o}}\mathrm{F}$
$b.\displaystyle \quad T_{\mathrm{F}}=\frac{9}{5}(56.7)+32=134.1^{\mathrm{o}}\mathrm{F}$
$c.\displaystyle \quad T_{\mathrm{F}}=\frac{9}{5}(31.1)+32=88.0^{\mathrm{o}}\mathrm{F}$
