University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 16 - Sound and Hearing - Problems - Exercises - Page 543: 16.80

Answer

(b) 0.75 mm.

Work Step by Step

In a standing wave pattern, the distance between antinodes $d = \lambda/2$. We know that $v = f\lambda \implies \lambda = v/f = \frac{1540}{10^6} = 1.54 \times 10^{-3} m = 1.54 m$. Then $d = \lambda/2 = 1.54/2 = 0.77 mm ≈ 0.75 mm,$ which is choice (b).
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