Answer
The power output of the star is $9.48\times 10^{27}~W$
Work Step by Step
We can find the power output of the star.
$P = I~A$
$P = I~(4\pi~r^2)$
$P = (15.4~W/m^2)~(4\pi)(7.00\times 10^{12}~m)^2$
$P = 9.48\times 10^{27}~W$
The power output of the star is $9.48\times 10^{27}~W$
