Answer
(a) $v = 0.96~m/s$
(b) $A = 0.265~m$
(c) $v = 0.96~m/s$
$A = 0.15~m$
Work Step by Step
(a) Since it takes 2.5 s to go from the highest point to the lowest point, it must be 5.0 s from one wave crest to the next. We can find the speed of the waves.
$v = \frac{distance}{time}$
$v = \frac{4.8~m}{5.0~s}$
$v = 0.96~m/s$
(b) The total distance from the highest point to the lowest point is 0.53 meters. The amplitude is half of this distance.
$A = \frac{0.53~m}{2} = 0.265~m$
(c) If the total vertical distance changed to 0.30 meters, the answer to part (a) would not change. The speed of the waves would still be 0.96 m/s. However, the answer to part (b) would change. The amplitude would be $\frac{0.30~m}{2}$, which is 0.15 meters.
