University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 14 - Periodic Motion - Problems - Exercises - Page 462: 14.45

Answer

(a) The pendulum bob reaches its highest speed in a time of 0.246 seconds. (b) The pendulum bob reaches its highest speed in a time of 0.246 seconds.

Work Step by Step

(a) We can find the period of the pendulum. $T = 2\pi~\sqrt{\frac{L}{g}}$ $T = 2\pi~\sqrt{\frac{0.240~m}{9.80~m/s^2}}$ $T = 0.9833~s$ Since the pendulum bob reaches its highest speed at the bottom of the swing, the pendulum bob reaches its highest speed after completing one-fourth of a cycle. We can find the time to reach the highest speed. $t = \frac{T}{4} = \frac{0.9833~s}{4} = 0.246~s$ The pendulum bob reaches its highest speed in a time of 0.246 seconds. (b) Since the period does not depend on the angle, the pendulum bob reaches its highest speed in a time of 0.246 seconds.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.