University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 14 - Periodic Motion - Problems - Discussion Questions - Page 459: Q14.8

Answer

See explanation.

Work Step by Step

Hang the ring on the chain and let it swing back and forth as a simple pendulum. The period of a simple pendulum is $T=2 \pi\sqrt{\frac{L}{g}}$. Gravity on Mars is about 38 percent of what it is on Earth, so the period of the pendulum would be longer (by a factor of $\sqrt{\frac{1}{0.38}}=1.62$) on Mars than on Earth.
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