Answer
(a) $3.49 \times 10^9$ J
(b) $-8.73 \times 10^7$ J
Work Step by Step
For (a):
The kinetic energy $K = \frac{1}{2} mv^2 = \frac{1}{2} (629)(3.33\times 10^3)^2 = 3.49 \times 10^9 J$
For (b):
The potential energy $U = -\frac{GMm}{r} = \frac{(6.67\times 10^{-11})(5.97 \times 10^{24})(629)}{2.87\times 10^9} = -8.73 \times 10^7 J$
