Answer
$$F=6612N$$
Work Step by Step
$w=mg=3400$
$\Sigma\tau=FL-wL=0$
$FrSin\theta - mgL=0$
Find the force needed to lift the ladder:
$F=\frac{mgL}{rSin\theta}$
$F=\frac{(3400)(10)}{8Sin(40)}= 6612 N$
University Physics with Modern Physics (14th Edition)
by Young, Hugh D.; Freedman, Roger A.
Published by
Pearson
ISBN 10:
0321973615
ISBN 13:
978-0-32197-361-0
Chapter 11 - Equilibrium and Elasticity - Problems - Exercises - Page 357: 11.5
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