Answer
a) $293 N$
b) $16.2 s^-2$
Work Step by Step
a)
$S* cos(\theta) = f + mg + F$
$S = (mg + F)/(cos(\theta)-sin(\theta) * u_k) = 293 N$
b)
$ a = (F*R - S * sin(\theta) * R * u_k)/I = 16.2 s^-2$
$S$ is the force that the rod exerts on the paper as it unrolls.
$u_k$ is the coefficient of kinetic friction between the roll of paper and the wall.
$I$ is the rod and paper’s moment of inertia.
$a$ is the anguar acceleration of the roll.
