Answer
We should walk 71.9 m at an angle of $64.1^{\circ}$ north of west.
Work Step by Step
We can find the west component $d_x$ of the direction $d$.
$d_x = 122.0~sin(58^{\circ}) - 72.0$
$d_x = 31.46~m$
We can find the north component $d_y$ of the direction $d$.
$d_y = 122.0~cos(58^{\circ})$
$d_y = 64.65~m$
We can use $d_x$ and $d_y$ to find the magnitude of the distance $d$.
$d = \sqrt{(31.46~m)^2+(64.65~m)^2}$
$d = 71.9~m$
We can find the angle north of west.
$tan(\theta) = \frac{64.65}{31.46}$
$\theta = tan^{-1}(\frac{64.65}{31.46}) = 64.1^{\circ}$
We should walk 71.9 m at an angle of $64.1^{\circ}$ north of west.
