University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 1 - Units, Physical Quantities, and Vectors - Problems - Exercises - Page 29: 1.35

Answer

a) 2.48 cm, 18.4° b) 4.09 cm, 83.7° c) 4.09 cm , 264°

Work Step by Step

a) A= 2.80 cm Ax = Acos(60) = 2.80 x cos(60) = 1.4 cm Ay= Asin(60) = 2.80 x sin(60) = 2.428 cm B= 1.90cm Bx= Bcos(60) = 1.90 x cos(60) = 0.95 cm By= Bsin(60) = 1.90 x sin(60) = -1.645 cm C= A + B Cx = Ax + Bx = 1.4 + 0.95 = 2.35 cm Cy= Ay + By = 2.428 - 1.645 = 0.783 cm C= ((Cx)^2 + (Cy)^2))^1/2 C= 2.4778 = 2.48 cm \theta = Tan^-1 (0.783/2.35) = 18.4° b) Ax= 1.4 cm ; Ay= 2.428 cm Bx= 0.95 cm ; By= -1.645 cm C = A - B Cx = Ax- Bx = 1.4 - 0.95 = 0.45 cm Cy = Ay - By = 2.428 + 1.645 = 4.073 cm C = ((0.45)^2 + (4.073)^2)^1/2 C= 4.09 cm \theta= Tan^-1(4.073/0.45) = 83.69° = 83.7° c) Ax= 1.4 cm ; Bx= 2.428 cm Ay= 0.95 cm ; By= - 1.645 cm C= B - A Cx = Bx - Ax = 0.95 - 1.4 = - 0.45 cm Cy = By - Bx = -1.645 - 2.428 = -4.073 cm C= ((-0.45)^2 + (-4.073)^2)^1/2 = 4.09 cm \theta = Tan^-1( -4.073/-0.45) = 83.7 ° 180° + 83.7° = 263.7° = 264°
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