Answer
$X_{CM}=6.5\times 10^{-12}m;Y_{CM}=0$
Work Step by Step
We can find the center of mass as follows:
Due to the symmetry $Y_{CM}=0$
and $X_{CM}=\frac{m_1x_1+m_2x_2}{m_1+m_2}$
We plug in the known values to obtain:
$X_{CM}=\frac{2(1.0u)(9.6\times 10^{-11}m)cos(\frac{104.5^{\circ}}{2})+(16u)(0)}{2(1.0u)+16u}$
$X_{CM}=6.5\times 10^{-12}m$
