Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 9 - Linear Momentum and Collisions - Problems and Conceptual Exercises - Page 294: 80

Answer

$33.2Kg$

Work Step by Step

We can find the mass of the hockey player as follows: $m_p=\frac{m_hv_h}{v_p}$ We plug in the known values to obtain: $m_p=\frac{-(1.3Kg)(6.5m/s)cos11^{\circ}}{-0.25m/s}$ $m_p=33.2Kg$
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