Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 9 - Linear Momentum and Collisions - Problems and Conceptual Exercises - Page 294: 75

Answer

$0.354mm$

Work Step by Step

We know that $\frac{m_tx_t+m_wX_{CM}}{m_t+m_w}=0$ This simplifies to: $X_{CM}=\frac{-m_tx_t}{m_w}$ We plug in the known values to obtain: $X_{CM}=-\frac{0.0502Kg}{35.5Kg}(25cm)$ $X_{CM}=-0.03535cm$ Since the distance is positive: $X_{CM}=0.03535cm=0.354mm$
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