Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 9 - Linear Momentum and Collisions - Problems and Conceptual Exercises - Page 293: 64

Answer

$\mathrm{B} < \mathrm{A} < \mathrm{C}$

Work Step by Step

The linear momentum of an object of mass $m$ moving with velocity $\vec{\mathrm{v}}$ is $\vec{\mathrm{p}}=m\vec{\mathrm{v}} \qquad$ 9-1 The kinetic energy of an object is $K=\displaystyle \frac{1}{2}mv^{2}$ --- $K=\displaystyle \frac{mv^{2}}{2}\cdot\frac{m}{m}=\frac{m^{2}v^{2}}{2m}=\frac{p^{2}}{2m}$ is a way of expressing kinetic energy with momentum and mass. $\displaystyle \mathrm{K}_{\mathrm{A}}=\frac{p^{2}}{2m},\quad$ $\displaystyle \mathrm{K}_{\mathrm{B}}=\frac{p^{2}}{2(2m)}=\frac{1}{2}\mathrm{K}_{\mathrm{A}}$ $\displaystyle \mathrm{K}_{\mathrm{C}}=\frac{p^{2}}{2(m/2)}=2\mathrm{K}_{\mathrm{A}}$ $\mathrm{B} < \mathrm{A} < \mathrm{C}$
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