Answer
$1.1KN$
Work Step by Step
We can find the required tension as follows:
$T=m(g\frac{2gL(1-cos\theta)}{L})$
$\implies T=mg(1+2(1-cos\theta))$
We plug in the known values to obtain:
$T=(78)(9.81)(3-2cos37^{\circ})$
$T=110N=1.1KN$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 8 - Potential Energy and Conservation of Energy - Problems and Conceptual Exercises - Page 249: 85
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