Answer
$1.8m$
Work Step by Step
We can find the required distance as follows:
$d=\frac{v_i^2}{2g(\mu_kcos\theta-sin\theta)}$
We plug in the known values to obtain:
$d=\frac{(1.56)^2}{2(9.81)((0.62)cos 28.4^{\circ}-sin 28.4^{\circ})}$
$d=1.8m$