Chapter 8 - Potential Energy and Conservation of Energy - Problems and Conceptual Exercises - Page 248: 56

$x=0.6m$ and $x=4.6m$

We can find the required locations as follows: $E=\frac{1}{2}mv^2+U$ We plug in the known values to obtain: $E=\frac{1}{2}(1.34)(1.25)+6.0$ $E=7.0J$ When we draw a horizontal line on the plot at $U=7.0 J$, we obtain the approximate locations as $x=0.6m$ and $x=4.6m$ and these are the turning points of the object.