Answer
$2.7\frac{m}{s}$
Work Step by Step
We know that
$W=E_f-E_i$
$W=(\frac{1}{2}mv_f^2+mgy_f)-(\frac{1}{2}mv_i^2+mgy_i)$
$\implies \frac{1}{2}mv_f^2=W-mgy_f+\frac{1}{2}mv_i^2+mgy_i$
This simplifies to:
$v_f=\sqrt{\frac{2W}{m}+2g(y_i-y_f)+v_i^2}$
We plug in the known values to obtain:
$v_f=\sqrt{\frac{2(-316)}{19}+2(9.81)(2.3-0)+(0)^2}$
$v_f=2.7\frac{m}{s}$
